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| Or LaPlace transforms. You'll be disgusted that you've been lied to throughout calculus that there's not an easier way to do everything. There is. {Proviso: I don't actually remember how to do LaPlace transforms. But they make everything easier.}
05-06-2008, 12:18 AM
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| jesse, with cubic functions, you can have either 1 real zero or 3. This is like some basic theorem of algebra or something. for xn, you can have n, n-2, n-4 etc real zeros. (you can have 0 zeros for an even function but must have at least one real zero for an odd function, that is, n is even or n is odd). since n=3 in this case, the function is odd and can have 3 or 1 real zeros.
05-06-2008, 01:12 AM
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No. Just no. Integrals and fun dont mix. I found them quite hard at first. Now I find them easy. But fun..? Naow. (with the possible exception of integration by inspection, which makes you look like a genius.) EDIT: Is it me or was that question piss easy? It just involves a bit of rearrangement and taking the cube root. Or am I missing something/cheating? EDITGA: Yeah, Im not cheating, and yeah its 4/3. Ahh, I love fractions. Otherwise Id be writing 1.33333333333333333333333333333333333333 3333333333333333333333333333333333333333 3333333333333333333333333333333333333333 3... (I think you get the point) Last edited by Vivisteiner; 05-06-2008 at 10:38 PM.
05-06-2008, 10:31 PM
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Yes. Just yes. Well, it's not exactly easy for someone who's never seen something like that before. It's like squares, but if you do that, then you're sure to get it wrong. Math causes psychological trauma, you know. People need examples first. Or you could follow significant figures, and in this problem, it'd be two figures (81 has the least sig figs).
05-06-2008, 10:58 PM
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