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#1 Our lab today was just to work two problems, and I really failed at them both. One of them was because of algebra and I'm hoping the other was also, but who knows?! a) If the soccer ball has an inertia of 600g, how fast would the larger 750g ball have to be travelling to exactly reverse the soccer ball's velocity? For this one, I wrote a couple of equations based off the conservation of momentum law and the definition of coefficient of restitution. Code: 1) [600g (m1) * 8 (v1)] - [750g (m2) * v (v2)] = [600g (m1) * -8 (reversed v1)] + [750g (m2) * v` (v4)] 2) v` = -.9v - .8 Anyways, equations for those: 1) P(sys)i = P(sys)f 2) e = (vel2f - vel1f)/(vel2i - vel1i) |
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| | for the first formula, using kg i got 12.8 = v2 + v4 Then with coefficient of restitution using this formula i got from wikipedia ![]() which is slightly different to your formula (particularly the bottom) I got 10(v4)+80 = 72 +9(v2) then using simultaneous equations with 12.8 -v2 = v4 and 10(v4)+80 = 72 + 9(v2) (subbing) i got v2 = 7.15789... or v2 = 136/19 but i could be wrong, this coefficient of restitution stuff is new to me. I might have gotten some of my negatives in the wrong place too. I dont think it has anything to do with newtons edit: you have to be pretty damn good at soccer to kick a ball and hit someone elses ball in mid air Last edited by blackmage_nuke; 09-20-2007 at 12:14 PM. |
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