Originally Posted by
Dante WolfWood ^ We had an hour discussion/argument today about His gun.
Now, the gun has three long barrels and loads/reloads like a breech loader shotgun: 3 shells at a time for each barrel.
now someone explain to me: How in the Hell does he load the gun and fire 27 bullets before having to reload again?
27/3=9
thats 9 shots; how does he shoot 9 times with 3 bullets?
It's a three-barreled revolver. 3 barrels x 6 rounds = 18 bullets. Since all three barrels fire together, he can fire six times before reloading. Note that I'm referring to the basic, unmodified Cerberus here.
It has a break-action reloading style (so far as I understand the term), but it's still a revolver. He can break it open, reload all 3 wheels at the same time, then get right back into it.
Considering how fast Vincent can reload, I'm guessing that each bunch of six bullets is attached together into a ring. That'd mean that one wheel could be fully reloaded in a single action, rather than having to load all six bullets separately. That'd be mean that reloading the entire gun would be a breeze.
11-02-2007, 08:16 PM
